In order to study the characteristics of a random process, let us look at some of the
basic properties and operations of a random process. Below we
will focus on the operations of the random signals that compose
our random processes. We will denote our random process with
XX and a random variable from a
random process or signal by xx.
Finding the average value of a set of random signals or random
variables is probably the most fundamental concepts we use in
evaluating random processes through any sort of statistical
method. The mean of a random process is the average
of all realizations of that process. In order to
find this average, we must look at a random signal over a
range of time (possible values) and determine our average from
this set of values. The mean, or average, of a
random process,
xt
xt
,
is given by the following equation:
m
x
t=
μ
x
t=X¯=EX=∫-∞∞xfxdx
m
x
t
μ
x
t
X
X
x
x
f
x
(1)
This equation may seem quite cluttered at first glance, but we
want to introduce you to the various notations used to
represent the mean of a random signal or process. Throughout
texts and other readings, remember that these will all equal
the same thing. The symbol,
μ
x
t
μ
x
t
, and the
X X with a bar
over it are often used as a short-hand to represent an
average, so you might see it in certain textbooks. The other
important notation used is,
EX
X
, which represents the "expected value of
XX" or the mathematical
expectation. This notation is very common and will appear
again.
If the random variables, which make up our random process, are
discrete or quantized values, such as in a binary process,
then the integrals become summations over all the possible
values of the random variable. In this case, our expected
value becomes
Exn=∑xαPrxn=α
x
n
x
α
x
n
α
(2)
If we have two random signals or variables, their averages can
reveal how the two signals interact. If the product of the two individual
averages of both signals do
not equal the
average of the product of the two signals, then the two
signals are said to be
linearly independent, also
referred to as
uncorrelated.
In the case where we have a random process in which only one
sample can be viewed at a time, then we will often not have
all the information available to calculate the mean using the
density function as shown above. In this case we must
estimate the mean through the time-average mean, discussed later. For
fields such as signal processing that deal mainly with
discrete signals and values, then these are the averages most
commonly used.
-
The expected value of a constant,
α α, is the constant:
Eα=α
α
α
(3)
-
Adding a constant, α
α, to each term increases the expected value by
that constant:
EX+α=EX+α
X
α
X
α
(4)
-
Multiplying the random variable by a constant,
α α, multiplies the
expected value by that constant.
EαX=αEX
α
X
α
X
(5)
-
The expected value of the sum of two or more random
variables, is the sum of each individual expected
value.
EX+Y=EX+EY
X
Y
X
Y
(6)
If we look at the second moment of the term
(we now look at
x2
x
2
in the integral), then we will have the mean-square
value of our random process. As you would expect, this
is written as
X2¯=EX2=∫-∞∞x2fxdx
X
2
X
2
x
x
2
f
x
(7)
This equation is also often referred to as the
average
power of a process or signal.
Now that we have an idea about the average value or values
that a random process takes, we are often interested in seeing
just how spread out the different random values might be. To
do this, we look at the variance which is a measure
of this spread. The variance, often denoted by
σ2
σ
2
, is written as follows:
σ2=VarX=EX-EX2=∫-∞∞x-X¯2fxdx
σ
2
Var
X
X
X
2
x
x
X
2
f
x
(8)
Using the rules for the expected value, we can rewrite this
formula as the following form, which is commonly seen:
σ2=X2¯-X¯2=EX2-EX2
σ
2
X
2
X
2
X
2
X
2
(9)
Another common statistical tool is the standard deviation.
Once you know how to calculate the variance, the standard
deviation is simply the square root of the
variance, or σ
σ.
-
The variance of a constant, α
α, equals zero:
Varα=σα2=0
Var
α
α
0
(10)
-
Adding a constant, α
α, to a random variable does not affect the
variance because the mean increases by the same value:
VarX+α=σX+α2=σX2
Var
X
α
X
α
X
(11)
-
Multiplying the random variable by a constant,
α α, increases the
variance by the square of the constant:
VarαX=σαX2=α2σX2
Var
α
X
α
X
α
2
X
(12)
-
The variance of the sum of two random variables only
equals the sum of the variances if the variable are
independent.
VarX+Y=σX+Y2=σX2+σY2
Var
X
Y
X
Y
X
Y
(13)
Otherwise, if the random variable are
not independent, then we must also
include the covariance of the product of the variables
as follows:
VarX+Y=σX2+2CovXY+σY2
Var
X
Y
X
2
Cov
X
Y
Y
(14)
In the case where we can not view the entire ensemble of the
random process, we must use time averages to estimate the
values of the mean and variance for the process. Generally,
this will only give us acceptable results for independent and
ergodic processes, meaning those processes in
which each signal or member of the process seems to have the
same statistical behavior as the entire process. The time
averages will also only be taken over a finite interval since
we will only be able to see a finite part of the sample.
For the ergodic random process,
xt
x
t
, we will estimate the mean using the time
averaging function defined as
X¯=EX=1T∫0TXtdt
X
X
1
T
t
0
T
X
t
(15)
However, for most real-world situations we will be dealing
with discrete values in our computations and signals. We
will represent this mean as
X¯=EX=1N∑n=1NXn
X
X
1
N
n
1
N
X
n
(16)
Once the mean of our random process has been estimated then
we can simply use those values in the following variance
equation (introduced in one of the above sections)
σ
x
2=X2¯-X¯2
σ
x
2
X
2
X
2
(17)
Let us now look at how some of the formulas and concepts above
apply to a simple example. We will just look at a single,
continuous random variable for this example, but the
calculations and methods are the same for a random process.
For this example, we will consider a random variable having
the probability density function described below and shown in
Figure 1.
fx=110if10≤x≤200otherwise
f
x
1
10
10
x
20
0
(18)
First, we will use Equation 1
to solve for the mean value.
X¯=∫1020x110dx=110x22|x=1020=110200-50=15
X
x
10
20
x
1
10
x
10
20
1
10
x
2
2
1
10
200
50
15
(19)
Using
Equation 7 we can
obtain the mean-square value for the above density function.
X2¯=∫1020x2110dx=110x33|x=1020=11080003-10003=233.33
X
2
x
10
20
x
2
1
10
x
10
20
1
10
x
3
3
1
10
8000
3
1000
3
233.33
(20)
And finally, let us solve for the variance of this function.
σ2=X2¯-X¯2=233.33-152=8.33
σ
2
X
2
X
2
233.33
15
2
8.33
(21)